1. Television channels are 20 MHz wide. How many bits/sec can be sent if 32-level digital signals are used? Assume a noiseless channel.
 Mbps

Nyquist Theory 2*20MHz*log232 = 2*20*5 = 200Mbps


2.7 signals, each requiring 4000 Hz, are multiplexed on to a single channel using FDM. How much minimum bandwidth is required for the multiplexed channel? Assume that the guard bands are 500 Hz wide.使用FDM将7个信号(每个都需要4000 Hz)复用到单个通道上。 多路复用通道需要多少最小带宽? 假设保护频带为500 Hz宽。

7 * 4000HZ + 6 * 500HZ = 31000HZ

【使用FDM:n个通道需要n-1个保护频带把它们隔开】 


3.Suppose that A, B, and C are simultaneously transmitting 0 bits, using a CDMA system with the chip sequence of figure following:

What is the resulting chip sequence? give your answer as (+x,-x,-x, …)

传0即传它的反码, (+3,+1,+1,-1,-3,-1,+1)


4.A CDMA receiver gets the following chips: (-1 +1 -3 +1 -1 -3 +1 +1). Assuming the chip sequences defined in figure following,

which stations transmitted, and which bits did each one send?
Choise the best answer

  • Station A send sent bit 1 sent bit 0 silence
  • Station B send sent bit 1 sent bit 0 silence
  • Station C send sent bit 1 sent bit 0 silence
  • Station D send sent bit 1 sent bit 0 silence

用CDMA的特性S*A*1/8 = CODE

得A = 1 B = -1 C = 0 D = 1


5.Q. A signal is transmitted digitally over a 4-kHz noiseless channel with one sample every 125 µsec. How many bits per second are actually sent for each of these encoding methods?
A. 1) CCITT 2.048 Mbps standard:  kbps
A. 2) DPCM with a 4-bit relative signal value:  kbps
A. 3) Delta modulationard:  kbps

64 32 8


6.Q. What is the percent overhead on a T1 carrier; that is, what percent of the 1.544 Mbps are not delivered to the end user? How about the E1 carrier ?
A. For the T1 carrier:  % (give your answer as an integer)

Hint: A T1 frame consists of 24 channels plus one extra bit for framing, each channel has 1 bit for signaling, 7 bits for data

A. For the E1 carrier:  % (give your answer as an integer)

Hint: Thirty of the E1 channels are used for information and two are used for signaling

13 6


7.Q. A simple telephone system consists of two end offices and a single toll office to which each end office is connected by a 1-MHz full-duplex trunk. The average telephone is used to make four calls per 8-hour workday. The mean call duration is 6 min. Ten percent of the calls are long-distance (i.e., pass through the toll office). What is the maximum number of telephones an end office can support? (Assume 4 kHz per circuit.)
A. 

Hint: Do you get how much time will a telephone occupy a circuit for an hour?

50000


8.What is the transmission unit for the physical layer?

  • bit
  • frame
  • packet
  • segment

Box 1: Select the best answer

A


9.A noiseless 2-k Hz channel is sampled every 1 msec. What is the maximum data rate?

  • 1000 bps
  • 2000 bps
  • 4000 bps
  • Can be infinite

Box 1: Select the best answer

D


10.The cable between toll office and the end office of telephone company are known as the
  • local loop
  • trunk
  • microwave line
  • coaxial cable

Box 1: Select the best answer

A


11.An T1 channel contains 24 PCM signals, its data rate is
  • 2.048 Mbps
  • 1.544 Mbps
  • 64 kbps
  • 100 Mbps

Box 1: Select the best answer

B


12.An E1 channel contains 32 PCM signals, its data rate is
  • 2.048 Mbps
  • 1.544 Mbps
  • 64 kbps
  • 10 Mbps

Box 1: Select the best answer

A


13.An E1 channel contains 32 PCM time slots, the data rate of each time slot channel is
  • 2.048 Mbps
  • 1.544 Mbps
  • 64 kbps
  • 10 Mbps

Box 1: Select the best answer

 C


14.If a binary signal is sent over a 16-kHz channel whose signal-to-noise ratio is 17 dB, what is the maximum achievable data rate?
 kbps

Shannon Theory Max data rate = 16kHz * log2(1+17) = 16*4.17 = 66.72

 


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